Optimal. Leaf size=227 \[ -\frac {\left (4 b c d+8 a d e-5 b e^2\right ) (e+2 d x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+e x+d x^2}}{64 d^3 (a+b x)}+\frac {(8 a d-5 b e+6 b d x) \sqrt {a^2+2 a b x+b^2 x^2} \left (c+e x+d x^2\right )^{3/2}}{24 d^2 (a+b x)}-\frac {\left (4 c d-e^2\right ) \left (4 b c d+8 a d e-5 b e^2\right ) \sqrt {a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac {e+2 d x}{2 \sqrt {d} \sqrt {c+e x+d x^2}}\right )}{128 d^{7/2} (a+b x)} \]
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Rubi [A]
time = 0.08, antiderivative size = 227, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 5, integrand size = 36, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.139, Rules used = {1014, 793, 626,
635, 212} \begin {gather*} -\frac {\sqrt {a^2+2 a b x+b^2 x^2} \left (4 c d-e^2\right ) \left (8 a d e+4 b c d-5 b e^2\right ) \tanh ^{-1}\left (\frac {2 d x+e}{2 \sqrt {d} \sqrt {c+d x^2+e x}}\right )}{128 d^{7/2} (a+b x)}-\frac {\sqrt {a^2+2 a b x+b^2 x^2} (2 d x+e) \sqrt {c+d x^2+e x} \left (8 a d e+4 b c d-5 b e^2\right )}{64 d^3 (a+b x)}+\frac {\sqrt {a^2+2 a b x+b^2 x^2} \left (c+d x^2+e x\right )^{3/2} (8 a d+6 b d x-5 b e)}{24 d^2 (a+b x)} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 626
Rule 635
Rule 793
Rule 1014
Rubi steps
\begin {align*} \int x \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+e x+d x^2} \, dx &=\frac {\sqrt {a^2+2 a b x+b^2 x^2} \int x \left (2 a b+2 b^2 x\right ) \sqrt {c+e x+d x^2} \, dx}{2 a b+2 b^2 x}\\ &=\frac {(8 a d-5 b e+6 b d x) \sqrt {a^2+2 a b x+b^2 x^2} \left (c+e x+d x^2\right )^{3/2}}{24 d^2 (a+b x)}-\frac {\left (b \left (4 b c d+8 a d e-5 b e^2\right ) \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int \sqrt {c+e x+d x^2} \, dx}{8 d^2 \left (2 a b+2 b^2 x\right )}\\ &=-\frac {\left (4 b c d+8 a d e-5 b e^2\right ) (e+2 d x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+e x+d x^2}}{64 d^3 (a+b x)}+\frac {(8 a d-5 b e+6 b d x) \sqrt {a^2+2 a b x+b^2 x^2} \left (c+e x+d x^2\right )^{3/2}}{24 d^2 (a+b x)}-\frac {\left (b \left (4 c d-e^2\right ) \left (4 b c d+8 a d e-5 b e^2\right ) \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int \frac {1}{\sqrt {c+e x+d x^2}} \, dx}{64 d^3 \left (2 a b+2 b^2 x\right )}\\ &=-\frac {\left (4 b c d+8 a d e-5 b e^2\right ) (e+2 d x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+e x+d x^2}}{64 d^3 (a+b x)}+\frac {(8 a d-5 b e+6 b d x) \sqrt {a^2+2 a b x+b^2 x^2} \left (c+e x+d x^2\right )^{3/2}}{24 d^2 (a+b x)}-\frac {\left (b \left (4 c d-e^2\right ) \left (4 b c d+8 a d e-5 b e^2\right ) \sqrt {a^2+2 a b x+b^2 x^2}\right ) \text {Subst}\left (\int \frac {1}{4 d-x^2} \, dx,x,\frac {e+2 d x}{\sqrt {c+e x+d x^2}}\right )}{32 d^3 \left (2 a b+2 b^2 x\right )}\\ &=-\frac {\left (4 b c d+8 a d e-5 b e^2\right ) (e+2 d x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+e x+d x^2}}{64 d^3 (a+b x)}+\frac {(8 a d-5 b e+6 b d x) \sqrt {a^2+2 a b x+b^2 x^2} \left (c+e x+d x^2\right )^{3/2}}{24 d^2 (a+b x)}-\frac {\left (4 c d-e^2\right ) \left (4 b c d+8 a d e-5 b e^2\right ) \sqrt {a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac {e+2 d x}{2 \sqrt {d} \sqrt {c+e x+d x^2}}\right )}{128 d^{7/2} (a+b x)}\\ \end {align*}
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Mathematica [A]
time = 0.46, size = 176, normalized size = 0.78 \begin {gather*} \frac {\sqrt {(a+b x)^2} \left (2 \sqrt {d} \sqrt {c+x (e+d x)} \left (8 a d \left (8 c d-3 e^2+2 d e x+8 d^2 x^2\right )+b \left (15 e^3-10 d e^2 x+8 d^2 e x^2+48 d^3 x^3+4 c d (-13 e+6 d x)\right )\right )+3 \left (4 c d-e^2\right ) \left (4 b c d+8 a d e-5 b e^2\right ) \log \left (e+2 d x-2 \sqrt {d} \sqrt {c+x (e+d x)}\right )\right )}{384 d^{7/2} (a+b x)} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 9 vs. order
3.
time = 0.10, size = 381, normalized size = 1.68
method | result | size |
risch | \(\frac {\left (48 b \,x^{3} d^{3}+64 a \,d^{3} x^{2}+8 b \,d^{2} e \,x^{2}+16 a \,d^{2} e x +24 b c \,d^{2} x -10 b d \,e^{2} x +64 a c \,d^{2}-24 d \,e^{2} a -52 b c d e +15 e^{3} b \right ) \sqrt {d \,x^{2}+e x +c}\, \sqrt {\left (b x +a \right )^{2}}}{192 d^{3} \left (b x +a \right )}+\frac {\left (-\frac {\ln \left (\frac {\frac {e}{2}+d x}{\sqrt {d}}+\sqrt {d \,x^{2}+e x +c}\right ) a c e}{4 d^{\frac {3}{2}}}+\frac {\ln \left (\frac {\frac {e}{2}+d x}{\sqrt {d}}+\sqrt {d \,x^{2}+e x +c}\right ) a \,e^{3}}{16 d^{\frac {5}{2}}}-\frac {\ln \left (\frac {\frac {e}{2}+d x}{\sqrt {d}}+\sqrt {d \,x^{2}+e x +c}\right ) b \,c^{2}}{8 d^{\frac {3}{2}}}+\frac {3 \ln \left (\frac {\frac {e}{2}+d x}{\sqrt {d}}+\sqrt {d \,x^{2}+e x +c}\right ) b c \,e^{2}}{16 d^{\frac {5}{2}}}-\frac {5 \ln \left (\frac {\frac {e}{2}+d x}{\sqrt {d}}+\sqrt {d \,x^{2}+e x +c}\right ) b \,e^{4}}{128 d^{\frac {7}{2}}}\right ) \sqrt {\left (b x +a \right )^{2}}}{b x +a}\) | \(302\) |
default | \(\frac {\mathrm {csgn}\left (b x +a \right ) \left (96 \left (d \,x^{2}+e x +c \right )^{\frac {3}{2}} d^{\frac {7}{2}} b x +128 \left (d \,x^{2}+e x +c \right )^{\frac {3}{2}} d^{\frac {7}{2}} a -80 \left (d \,x^{2}+e x +c \right )^{\frac {3}{2}} d^{\frac {5}{2}} b e -96 \sqrt {d \,x^{2}+e x +c}\, d^{\frac {7}{2}} a e x -48 \sqrt {d \,x^{2}+e x +c}\, d^{\frac {7}{2}} b c x +60 \sqrt {d \,x^{2}+e x +c}\, d^{\frac {5}{2}} b \,e^{2} x -48 \sqrt {d \,x^{2}+e x +c}\, d^{\frac {5}{2}} a \,e^{2}-24 \sqrt {d \,x^{2}+e x +c}\, d^{\frac {5}{2}} b c e +30 \sqrt {d \,x^{2}+e x +c}\, d^{\frac {3}{2}} b \,e^{3}-96 \ln \left (\frac {2 \sqrt {d \,x^{2}+e x +c}\, \sqrt {d}+2 d x +e}{2 \sqrt {d}}\right ) a c \,d^{3} e +24 \ln \left (\frac {2 \sqrt {d \,x^{2}+e x +c}\, \sqrt {d}+2 d x +e}{2 \sqrt {d}}\right ) a \,d^{2} e^{3}-48 \ln \left (\frac {2 \sqrt {d \,x^{2}+e x +c}\, \sqrt {d}+2 d x +e}{2 \sqrt {d}}\right ) b \,c^{2} d^{3}+72 \ln \left (\frac {2 \sqrt {d \,x^{2}+e x +c}\, \sqrt {d}+2 d x +e}{2 \sqrt {d}}\right ) b c \,d^{2} e^{2}-15 \ln \left (\frac {2 \sqrt {d \,x^{2}+e x +c}\, \sqrt {d}+2 d x +e}{2 \sqrt {d}}\right ) b d \,e^{4}\right )}{384 d^{\frac {9}{2}}}\) | \(381\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.52, size = 394, normalized size = 1.74 \begin {gather*} \left [\frac {3 \, {\left (16 \, b c^{2} d^{2} + 32 \, a c d^{2} e - 24 \, b c d e^{2} - 8 \, a d e^{3} + 5 \, b e^{4}\right )} \sqrt {d} \log \left (8 \, d^{2} x^{2} + 8 \, d x e - 4 \, \sqrt {d x^{2} + x e + c} {\left (2 \, d x + e\right )} \sqrt {d} + 4 \, c d + e^{2}\right ) + 4 \, {\left (48 \, b d^{4} x^{3} + 64 \, a d^{4} x^{2} + 24 \, b c d^{3} x + 64 \, a c d^{3} + 15 \, b d e^{3} - 2 \, {\left (5 \, b d^{2} x + 12 \, a d^{2}\right )} e^{2} + 4 \, {\left (2 \, b d^{3} x^{2} + 4 \, a d^{3} x - 13 \, b c d^{2}\right )} e\right )} \sqrt {d x^{2} + x e + c}}{768 \, d^{4}}, \frac {3 \, {\left (16 \, b c^{2} d^{2} + 32 \, a c d^{2} e - 24 \, b c d e^{2} - 8 \, a d e^{3} + 5 \, b e^{4}\right )} \sqrt {-d} \arctan \left (\frac {\sqrt {d x^{2} + x e + c} {\left (2 \, d x + e\right )} \sqrt {-d}}{2 \, {\left (d^{2} x^{2} + d x e + c d\right )}}\right ) + 2 \, {\left (48 \, b d^{4} x^{3} + 64 \, a d^{4} x^{2} + 24 \, b c d^{3} x + 64 \, a c d^{3} + 15 \, b d e^{3} - 2 \, {\left (5 \, b d^{2} x + 12 \, a d^{2}\right )} e^{2} + 4 \, {\left (2 \, b d^{3} x^{2} + 4 \, a d^{3} x - 13 \, b c d^{2}\right )} e\right )} \sqrt {d x^{2} + x e + c}}{384 \, d^{4}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x \sqrt {c + d x^{2} + e x} \sqrt {\left (a + b x\right )^{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 4.21, size = 268, normalized size = 1.18 \begin {gather*} \frac {1}{192} \, \sqrt {d x^{2} + x e + c} {\left (2 \, {\left (4 \, {\left (6 \, b x \mathrm {sgn}\left (b x + a\right ) + \frac {8 \, a d^{3} \mathrm {sgn}\left (b x + a\right ) + b d^{2} e \mathrm {sgn}\left (b x + a\right )}{d^{3}}\right )} x + \frac {12 \, b c d^{2} \mathrm {sgn}\left (b x + a\right ) + 8 \, a d^{2} e \mathrm {sgn}\left (b x + a\right ) - 5 \, b d e^{2} \mathrm {sgn}\left (b x + a\right )}{d^{3}}\right )} x + \frac {64 \, a c d^{2} \mathrm {sgn}\left (b x + a\right ) - 52 \, b c d e \mathrm {sgn}\left (b x + a\right ) - 24 \, a d e^{2} \mathrm {sgn}\left (b x + a\right ) + 15 \, b e^{3} \mathrm {sgn}\left (b x + a\right )}{d^{3}}\right )} + \frac {{\left (16 \, b c^{2} d^{2} \mathrm {sgn}\left (b x + a\right ) + 32 \, a c d^{2} e \mathrm {sgn}\left (b x + a\right ) - 24 \, b c d e^{2} \mathrm {sgn}\left (b x + a\right ) - 8 \, a d e^{3} \mathrm {sgn}\left (b x + a\right ) + 5 \, b e^{4} \mathrm {sgn}\left (b x + a\right )\right )} \log \left ({\left | -2 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + x e + c}\right )} \sqrt {d} - e \right |}\right )}{128 \, d^{\frac {7}{2}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int x\,\sqrt {{\left (a+b\,x\right )}^2}\,\sqrt {d\,x^2+e\,x+c} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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